3y^2+109y-616=0

Solution for 3y^2+109y-616=0 equation:

3y^2+109y-616=0

a = 3; b = 109; c = -616;
Δ = b2-4ac
Δ = 1092-4·3·(-616)
Δ = 19273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(109)-\sqrt{19273}}{2*3}=\frac{-109-\sqrt{19273}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(109)+\sqrt{19273}}{2*3}=\frac{-109+\sqrt{19273}}{6}
$